For Career Guidance: TopCoaching.com  |  (011)45-629-346  |  Log In  |  Register Free
topMCAcoaching
Home Frequently Asked Questions

Frequently Asked Questions by Members

FAQShowing All Questions asked by Members

Showing 1 to 20 out of 28 Doubts
  • How to find total no of divisors of any number and how to calculate sum of all factors of any natural number?Please explain it with an example.

  • regarding this conclusion  i have doubt "Required function  = W x Wconjugate = |W|2"

    when w is in form of  (1 ir)
    then |W| = |1 ir|

    and |W|^2 = |1 ir|^2
                     = 1 2 * 1 * ir ir^2
                     = 1 2*ir - r^2

    so how it will be equal to (1 r^2)  = |W|^2
    thnks


  • Given a function       (denotes product)
    ,    where r is a natural number. Then the value of the function , when r is very large, will be 1)
    2)
    3)
    4)

  • ____ apples are grown in WashingtonState. 1)Best 2)The most good 3)The best 4)The better 5)None of these In general there should be no article in front on the noun.So the answer might be no 1.why the answer will be no.3?

  • If (x – 5)(y 6)(z – 8) = 1331, then the minimum value of x y z is: 1) 40
    2) 33
    3) 19
    4) 45
    5) Not unique
    Correct Answer: 1 Your Answer: Not Attempted Course: CAT Quantitative Answer Description
    The minimum Sum is obtained when (x – 5) = (y 6) = (z – 8) Hence (x – 5) = (y 6) = (z – 8) = 11 => x = 16, y = 5, z = 19 Thus (x y z) = 40
    Q20) If x y z = 21, then the maximum value of (x – 6)(y 7) (z – 4) is: 1) 343
    2) 216
    3) 125
    4) 64
    5) None of these
    Correct Answer: 2 Your Answer: Not Attempted Course: CAT Quantitative Answer Description
    (x – 6)(y 7)(z – 4) will be maximum only when (x – 6) = (y 7) = (z – 4) = k (say) for a given value of (x y z) = 21 => x = k 6 => y = k – 7 => z = k 4 x y z = 21 =>(k 6) (k – 7) (k 4) = 21 =>3k 3 = 21 =>k = 6   Therefore, (x – 6).(y 7)(z – 4) = k3 = (6)3 = 216

    i didnt understand the answer plz clarifythnx

  •  1. the number of ordered triplets of positive integers which are the solutions of the equation x y z=100 is
    a)5081 b)6005 c)4851 d)6273.

    2. the number of ways in which Rs 20  can be distriuted among five children such that no one receives than Rs 3 is
    a)125 b)126 c)127 d)128.

     3. 2nC3 :nC2 =11 :1 then n is
    a)5 b)4 c)6 d)8.

    4. the number of different words ending and begining with a consonant which can be made out of the letters of the word EQUATION is
    a)5200 b)4320 c)1295 d)3000.

    5. the number of different words that can be formed out of the letters of the word MORADABAD taken four a time is
    a)500 b)600 c)620 d)626.

    6. numbers lying between 99 and 1000 can be formed from the digits2,3,7,0,8,6 are
    a)100 b)150 c)200 d)250.

     7. how many triangles can be drawn through n given points on a cricle?

  • Three friends divided some bullets equally. After all of them shot 4 bullets the total number of bullets remaining is equal to the bullets each had after division. Find the original number divided

  • 1. find the number of numbers between 100 to 400 which are divisble by either 2,3,5,or 7.

    2.find th enumber of numbers between 300 to 400 which are not divisble by 2,3 ,5 and 7.

    find the last digit in the expression( 36472)123! x (3476)76!  .

    3.how can we determine that m! ,where m is any natural number, is of which form wether 4n or 4n 1 or 4n 2 or 4n 3.

    4.find the  unit digit in each of following expression
    a. 22x44x66x88
    b.1x22x33x44x......x100100
    c. 37123x43144x57266x32157x525!

  • in which month exam occure

  • wat is meaning of ascii code

  • wat is syllabus & also wat book refer 4 mca entrace & wat entrance exam 4 iim institute

  • what should i do for taking free online course for doing mca

  • 1) Find all numbers of the form 517xy that are divisible by 89.

    2) Find the remainder which 73 75 78 57 197 is divided by 34
    a.34
    b.30
    c.15
    d.28

    3)Find the remainder when 73x75x78x57x197 is divisible by 34
    a.32
    c.30
    c.15
    d.28

    4)Find the remainder when 73x75x78x57x197x37 is divided by 34
    a.32
    b.30
    c.15
    d.28

    5)find the remainder when 43197 is divided by 7
    a 2
    b 4
    c 6
    d 1

  • well..does any quetion comes beyond your study material ,in the entrance examination??

  • A sum of money kept in a bank and 1600 in 10 years at simle interest.Find the sum .
    a 800
    b 1000
    c 900
    d none

  • The least value of n for which the sum of series 5 8 11 ---- n terms is not less than 670 is
    a 20
    b 19
    c 22
    d 18

    The sum of the numbers from 1 to 100 which are not divisble by 3 and 5 is
    a 2946
    b 2732
    c 2632
    d 2317

    If all the 6's are eplaced by 9's then the algebric sum of all the numbers from 1 to 100 <both Inclusive > varies by
    a 330
    b 333
    c 219
    d 279

  • 1. The number of term common to two terms APs
    3,7,11,.....,407 and
    2,9,16,.....,709

    2. Two persons Ramu and Kalu have joined some work.Ramu and Kalu started with an intial salary of 500/- and 640/- respectively with annual increments of 25/- and 30/- each respectively.In twhich year will Ramu earning more salary than Kalu?


  • FIND THE NUMBER OF DIVISORS OF 1080 EXCLUDING THE THROUGHOUT DIVISORS,WHICH ARE PERFEST SQAURE.
    (a) 28
    (b) 29
    (c) 30
    (d) 31

    find the number of divisors of 544excliding 1 and 544
    (a)12
    (b) 18
    (c) 11
     (d)10
     
    find the number of divisors 544 which are greater than 3
    (a)15
    (b)10
    (c)12
    (d) none

    find the sum of divisors of 544 excludingiding 1 and 544
    (a)1089
    (b)545
    (C)589
    (d)1134
     
    find the sum of divisors of 544which are perfect square
    (a)32
    (b)64
    (c)42
    (d)21

    find the sum of odd divisoesof 544
    (a)18
    (b)34
    (c)68
    (d)36

    find the sum of even divisors of 4096
    (a)8192
    (b)6144
    (c)8190
    (d)6142


  • hello....m pursuing bca 2nd year....jus completed now...now m in 3rd year....plz can u tell me wat can i do for my MCA entrance xmz prep........from where i get the best coaching..how can i prepare for that..........

  • if (1+x-2x2)6 = 1 + a1x+a2x2+......+a12x12, then the value of
    a2 +a4 + a6 +...+a12 is
    (a) 1024
    (b) 64
    (c) 32
    (d) 31
     2) if 0< a<b<c and the roots x1 and x2 of the equations ax2+bx +c=0 are imaginery then
    a. |x1 |=|x2|  or |x1|>1
    b. |x1|= 1
    c.  |x2|<1
    d.  none of these
    please explain

Showing 1 to 20 out of 28 Doubts
IIT & AIEEE  |  AIPMT, AIIMS & AFMC  |  CA-CPT  |  BBA, BBS & BBE  |  CLAT  |  CAT  |  Bank PO  |  GRE  |  GMAT  |  Career Guidance

© 2011 Prism Education Private Limited. All rights Reserved.